-2x^2+0,5=0

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Solution for -2x^2+0,5=0 equation: 



-2x^2+0.5=0

a = -2; b = 0; c = +0.5;
Δ = b2-4ac
Δ = 02-4·(-2)·0.5
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2}{2*-2}=\frac{-2}{-4}
=1/2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2}{2*-2}=\frac{2}{-4}
=-1/2
$

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